0.18t^2-2t-5.6=0

Solution for 0.18t^2-2t-5.6=0 equation:

0.18t^2-2t-5.6=0

a = 0.18; b = -2; c = -5.6;
Δ = b2-4ac
Δ = -22-4·0.18·(-5.6)
Δ = 8.032
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{8.032}}{2*0.18}=\frac{2-\sqrt{8.032}}{0.36}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{8.032}}{2*0.18}=\frac{2+\sqrt{8.032}}{0.36}
$